Difference between revisions of "Dose Calculation"

Revision as of 16:23, 5 November 2009

Dose (C/cm):

${\frac {\#e}{1cm}}\cdot 1.60\cdot 10^{{-19}}C/e\cdot gasgain$

$3.6\cdot 10^{{11}}\times 1.6\cdot 10^{{-19}}\times 2\cdot 10^{{5}}=0.01~C/cm$

$1.2\cdot 10^{{11}}\times 1.6\cdot 10^{{-19}}\times 2\cdot 10^{{5}}=0.004~C/cm$

$1.4\cdot 10^{{11}}\times 1.6\cdot 10^{{-19}}\times 2\cdot 10^{{5}}=0.004~C/cm$

$2.9\cdot 10^{{11}}\times 1.6\cdot 10^{{-19}}\times 2\cdot 10^{{5}}=0.009~C/cm$

EM background: $40~kHz/straw$ or $267~Hz/cm$

1 year of running (= 1/3 year beam on target) = $1.1\cdot 10^{{7}}s\times 267{\frac {e}{s\cdot cm}}\times 1.60\cdot 10^{{-19}}C/e\times 2\cdot 10^{{5}}=9.0\cdot 10^{{-5}}C/cm$

@@ Line 19: / Line 19: @@
 EM background: <math>40~kHz/straw</math>or <math>267~Hz/cm</math>
-* 1 year of running (= 1/3 year beam on target) = <math>1.1\cdot 10^{7}s \times 267 e/s\cdot cm \times 1.60\cdot10^{-19}C/e \times 2\cdot 10^{5} = 9.0 \cdot 10^{-5} C/cm</math>
+* 1 year of running (= 1/3 year beam on target) = <math>1.1\cdot 10^{7}s \times 267 \frac{e}{s\cdot cm} \times 1.60\cdot10^{-19}C/e \times 2\cdot 10^{5} = 9.0 \cdot 10^{-5} C/cm</math>
 * Irradiation dose = 44 years of running